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Drafting is not for the faint of heart. Sadly, there’s no help in.Q:

Are there any local factors of $\mathrm{SO}(2)$ of order $\leq 5$?

Let $n$ be an integer $\geq 1$. A local factor of $S_n$ is a normal subgroup of $S_n$ of finite index. In the case $n = 2$, a result due to Lazard (Théorie de Brauer et algebres de Lie nilpotentes (1966) Colloque C. Chevalley) and later generalised by Neumann (Local analysis of groups of nilpotent type (1968) C.R.Acad.Sc.Paris) says that every local factor of $S_2$ is the direct product of a cyclic group of order $\leq 2$ and a Sylow $2$-subgroup $P$ of $S_2$.
Are there any local factors of $\mathrm{SO}(2)$ of order $\leq 5$?

To answer the question as asked, no, there is a group of order 5. To see this one can use the Classification of Finite Simple Groups to see that there is a group of order 5. You can find the structure of this group in Dynkin’s paper from 1959. I give the structure in the case that $5=2^2.3$. Let $P_5= \langle a,b \mid a^4=b^2=e, ba=a^3b
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