Newstar Jimmy Tonik Mega Fix

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Newstar Jimmy Tonik Mega

A: It looks like you are trying to search the text of the file for the keywords you have provided. Rather, you have to read the file line by line. Here is an example. #!/bin/bash keywords=’unix’ read -r -p “Search for: ” line while read -r line; do if [[ $line =~ (^| )$keywords (($| )) ]]; then # Check the rest of the line sed ‘1:;/^.\{1,10\}$/d;$d;s/[ \t]*$//’ “$line” > “$line-modified” # Check the rest of the line sed ‘1:;/^.\{1,10\}$/d;$d;s/[ \t]*$//’ “$line-modified” > “$line” fi done Q: $\limsup\limits_{n \to \infty} \frac{\sqrt{n+\sqrt{n+\sqrt{n+…}}} – \sqrt{2}}{(\sqrt{n}-\sqrt{2})^{1/3}} = \sqrt[3]{2}$ Can someone help me, how to prove this? $$\limsup\limits_{n \to \infty} \frac{\sqrt{n+\sqrt{n+\sqrt{n+…}}} – \sqrt{2}}{(\sqrt{n}-\sqrt{2})^{1/3}} = \sqrt[3]{2}$$ I tried to find the upper bound, but it takes the argument of the $\limsup$ to infinity. Is there any other way? Thanks in advance! A: I think I have found a solution. $$\limsup\limits_{n \to \infty} \frac{\sqrt{n+\sqrt{n+\sqrt{n+…}}} – \sqrt{2}}{(\sq

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